A constructor can have at most one 'super' initializerDRT-W1496

The analyzer produces this diagnostic when the initializer list of a constructor contains more than one invocation of a constructor from the superclass. The initializer list is required to have exactly one such call, which can either be explicit or implicit.

Example

The following code produces this diagnostic because the initializer list for B's constructor invokes both the constructor one and the constructor two from the superclass A:

class A {
  int? x;
  String? s;
  A.one(this.x);
  A.two(this.s);
}

class B extends A {
  B() : super.one(0), super.two('');
}

Common fixes

If one of the super constructors will initialize the instance fully, then remove the other:

class A {
  int? x;
  String? s;
  A.one(this.x);
  A.two(this.s);
}

class B extends A {
  B() : super.one(0);
}

If the initialization achieved by one of the super constructors can be performed in the body of the constructor, then remove its super invocation and perform the initialization in the body:

class A {
  int? x;
  String? s;
  A.one(this.x);
  A.two(this.s);
}

class B extends A {
  B() : super.one(0) {
    s = '';
  }
}

If the initialization can only be performed in a constructor in the superclass, then either add a new constructor or modify one of the existing constructors so there's a constructor that allows all the required initialization to occur in a single call:

class A {
  int? x;
  String? s;
  A.one(this.x);
  A.two(this.s);
  A.three(this.x, this.s);
}

class B extends A {
  B() : super.three(0, '');
}